Brayton Cycle.

The gas-turbine cycle — steady flow through a compressor, a combustor and a turbine, where the compressor eats a third of the output.

Mode

The machine — The gas-turbine cycle — steady flow through a compressor, a combustor and a turbine, where the compressor eats a third of the output.

Diagram
00.2000.4000.6000.8001.01.21.41.61.82.02.2200400600800100012001→2: Adiabatic compression2→3: Heat added in the combustor3→4: Adiabatic expansion through the turbine4→1: Heat rejected to atmosphere1State 1 — Compressor inlet2State 2 — Compressor discharge3State 3 — Turbine inlet — combustor exit4State 4 — Turbine exhaustSpecific volume vPressure P

Press Run to turn the machine over. Space runs and pauses, R resets, and the arrow keys step through the cycle one process at a time.

isentropic 1→2 · Adiabatic compression q 0 w -311.6 kJ/kg

Thermal efficiency

50.83%

Carnot limit, same span

80%

Net work

454.4 kJ/kg

Heat added

893.8 kJ/kg

Heat rejected

439.5 kJ/kg

Peak temperature

1,500 K

Lowest temperature

300 K

Back work ratio

0.407

Every setting is inside its sensible range for this cycle. Push a slider to an extreme and anything worth knowing about will appear here.

State points — the cycle, one corner at a time

State What just happened P kPa v m³/kg T K s kJ/kg·K
1 Compressor inlet 100 0.861 300 0
2 Compressor discharge 1,200 0.1459 610 0
3 Turbine inlet — combustor exit 1,200 0.3587 1,500 0.904
4 Turbine exhaust 100 2.1166 737 0.904

Adiabatic compression · Constant-pressure combustion · Adiabatic expansion · Constant-pressure heat rejection

Starting points Pick one, then move any slider from there.

A mid-sized machine driving a generator or a pipeline compressor. Look at the back work ratio: a third of the turbine’s output goes straight back into the compressor.

12
1,500 K
300 K

How the Brayton cycle works

The Brayton cycle takes its working fluid through 4 processes and returns it to the state it began in. In order, those are:

  1. Adiabatic compression
  2. Constant-pressure combustion
  3. Adiabatic expansion
  4. Constant-pressure heat rejection

You will find it in jet engines and power-station gas turbines. At the standard set-up above — pressure ratio 12, peak temperature 1,500 K, intake temperature 300 K — it reaches a thermal efficiency of 50.83%, against a Carnot limit of 80.00% for the same temperature span. The net work is 454.4 kJ/kg, from 893.8 kJ/kg of heat in and 439.5 kJ/kg rejected.

Its efficiency has a closed form: η = 1 − 1/rₚ^((γ−1)/γ). The simulator above does not use it — it solves the state points and divides net work by heat in — but the two agree to machine precision, and the test suite behind this page checks that on every build.

Reading the two diagrams

Switch the diagram pane between P–v and T–s and watch the same cycle change costume. On the pressure–volume plot the area inside the loop is the net work per kilogram of working fluid, because work is the integral of P dv. On the temperature–entropy plot the area inside the loop is the net heat, because heat in a reversible process is the integral of T ds.

Those two areas are the same number. That is the first law applied to a closed loop: the fluid ends where it started, so its internal energy has not changed, so everything that went in as heat came out as work. Two different pictures, one arithmetic.

The T–s view is the more revealing of the two once you are comfortable with it, because it shows the temperature at which heat crossed the boundary — and that, not the amount, is what decides how much of it can become work.

A piston engine’s name on a turbine’s cycle

George Brayton built a constant-pressure combustion engine in the 1870s. It was a piston machine, and it was not a commercial success. What survived is the cycle: steady compression, heat added at constant pressure, steady expansion — which turned out to describe something Brayton never built.

A gas turbine has no pistons, no crank and no flywheel. Air flows continuously through a compressor, into a combustor that burns fuel in it at roughly constant pressure, and out through a turbine that extracts work. Nothing reciprocates. It is the same cycle as Brayton’s engine, in a completely different machine.

The compressor eats first

Look at the back work ratio on the panel. In a piston engine, compression and expansion happen in the same cylinder at different times, and the flywheel carries the energy across. In a gas turbine they happen at the same instant in different components, and the turbine has to drive the compressor continuously through a shaft before it drives anything else. At a pressure ratio of 12 that is roughly 40% of the turbine's gross output, gone before the machine produces anything at all.

This is why the gas turbine took so long to arrive. The thermodynamics were understood in the nineteenth century; the problem was that early compressors were inefficient enough that the turbine could not both drive them and produce useful work. The engine had to wait for aerodynamics.

Blades hotter than their own melting point

Efficiency here rises with pressure ratio and with nothing else — set the peak temperature anywhere and the efficiency card will not move. But peak temperature decides the work per kilogram of air, which decides how big the engine has to be for a given output, so every generation of gas turbine has pushed turbine inlet temperature as hard as materials allow.

They have pushed it past the melting point of the alloys. Modern first-stage turbine blades are grown as single crystals to remove grain boundaries that would creep, coated in ceramic thermal barriers, and shot through with internal passages that bleed cooler compressor air out over the surface as a film. The gas is hotter than the metal could survive standing still in it.

Brayton cycle — common questions

What is the back work ratio, and why does it matter so much here?

It is the compressor's work as a fraction of the turbine's. In a gas turbine the turbine drives the compressor directly, so that fraction never leaves the machine — often a third or more. A steam plant pumps an almost incompressible liquid instead, and its equivalent figure is close to zero, which is exactly why the Rankine cycle beats a gas cycle at the same temperatures.

Does a hot day make a gas turbine less efficient?

Not by the cycle's own arithmetic — efficiency depends on pressure ratio alone, and the panel above will show exactly the same figure at 300 K and 320 K inlet. What falls is the work per kilogram of air, by around 5%, and a real machine also breathes thinner air. Gas turbines lose output in summer, but not because the cycle got worse.

Why does raising the pressure ratio always raise efficiency here?

Because the ideal air-standard expression is η = 1 − 1/rₚ^((γ−1)/γ), which rises without limit. Real machines stop long before the maths does: the compressor gets longer, heavier and harder to keep out of surge, and the air leaving it gets hot enough to be a problem in its own right.

Is a jet engine a Brayton cycle?

Its core is. The difference is what happens to the expansion: a power-generating turbine extracts all of it as shaft work, while a turbojet extracts only enough to drive the compressor and leaves the rest as a high-velocity jet for thrust. Same cycle, different way of collecting the output.

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